Circles

Mathematical Structure (Expanded) — MathJax Frontend
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Foundations
\$begin:math:display$ \\\\mathbb{N}=\\\\{0,1,2,3,\\\\dots\\\\},\\\\quad \\\\mathbb{Z}=\\\\{\\\\dots,-2,-1,0,1,2,\\\\dots\\\\},\\\\quad \\\\mathbb{Q}=\\\\left\\\\{\\\\frac{p}{q}:p\\\\in\\\\mathbb{Z},\\\\ q\\\\in\\\\mathbb{Z}\\\\setminus\\\\{0\\\\}\\\\right\\\\} \\$end:math:display$
\$begin:math:display$ \\\\mathbb{R}=\\\\text{completion}(\\\\mathbb{Q})\\\\text{ under }d(x,y)=|x-y|,\\\\quad \\\\mathbb{C}=\\\\{a+bi:a,b\\\\in\\\\mathbb{R},\\\\ i^2=-1\\\\} \\$end:math:display$
\$begin:math:display$ \\\\forall a,b,c\\\\in\\\\mathbb{R}: \\\\ a+b=b+a,\\\\ (a+b)+c=a+(b+c),\\\\ a(b+c)=ab+ac,\\\\ a\\\\cdot 1=a,\\\\ a+0=a \\$end:math:display$
\$begin:math:display$ \\\\forall a\\\\in\\\\mathbb{R}\\\\setminus\\\\{0\\\\}: \\\\ a\\\\cdot a^{-1}=1,\\\\quad \\\\frac{a}{b}=a\\\\cdot b^{-1}\\\\ (b\\\\neq 0) \\$end:math:display$
Limits and Continuity
\$begin:math:display$ \\\\lim_{x\\\\to a}f(x)=L\\\\ \\\\Longleftrightarrow\\\\ \\\\forall\\\\varepsilon>0\\\\ \\\\exists\\\\delta>0: \\\\ 0<|x-a|<\\\\delta\\\\Rightarrow |f(x)-L|<\\\\varepsilon \\$end:math:display$
\$begin:math:display$ f\\\\text{ continuous at }a\\\\ \\\\Longleftrightarrow\\\\ \\\\lim_{x\\\\to a}f(x)=f(a) \\$end:math:display$
\$begin:math:display$ \\\\lim_{x\\\\to 0}\\\\frac{\\\\sin x}{x}=1,\\\\quad \\\\lim_{x\\\\to 0}\\\\frac{1-\\\\cos x}{x^2}=\\\\frac12,\\\\quad \\\\lim_{n\\\\to\\\\infty}\\\\left(1+\\\\frac{x}{n}\\\\right)^n=e^x \\$end:math:display$
Series Expansions
\$begin:math:display$ e^x=\\\\sum_{n=0}^{\\\\infty}\\\\frac{x^n}{n!} \\$end:math:display$
\$begin:math:display$ \\\\sin x=\\\\sum_{n=0}^{\\\\infty}(-1)^n\\\\frac{x^{2n+1}}{(2n+1)!},\\\\quad \\\\cos x=\\\\sum_{n=0}^{\\\\infty}(-1)^n\\\\frac{x^{2n}}{(2n)!} \\$end:math:display$
\$begin:math:display$ \\\\frac{1}{1-x}=\\\\sum_{n=0}^{\\\\infty}x^n\\\\ (|x|<1),\\\\quad \\\\ln(1+x)=\\\\sum_{n=1}^{\\\\infty}(-1)^{n-1}\\\\frac{x^n}{n}\\\\ (|x|<1) \\$end:math:display$
Circle Definitions and Equivalences
\$begin:math:display$ S^1(r)=\\\\{(x,y)\\\\in\\\\mathbb{R}^2:\\\\ x^2+y^2=r^2\\\\},\\\\quad D=2r \\$end:math:display$
\$begin:math:display$ \\\\pi=\\\\frac{C}{D}=\\\\frac{C}{2r},\\\\quad C=2\\\\pi r \\$end:math:display$
\$begin:math:display$ A=\\\\pi r^2=\\\\frac12Cr \\$end:math:display$
\$begin:math:display$ \\\\pi=4\\\\arctan(1)=4\\\\int_{0}^{1}\\\\frac{1}{1+x^2}\\\\,dx \\$end:math:display$
\$begin:math:display$ \\\\pi=2\\\\int_{0}^{1}\\\\frac{1}{\\\\sqrt{1-x^2}}\\\\,dx \\$end:math:display$
Rhind Papyrus Approximation as Algebra
\$begin:math:display$ A\\\\approx\\\\left(D-\\\\frac{D}{9}\\\\right)^2=\\\\left(\\\\frac{8D}{9}\\\\right)^2=\\\\frac{64D^2}{81} \\$end:math:display$
\$begin:math:display$ A=\\\\frac{\\\\pi D^2}{4} \\$end:math:display$
\$begin:math:display$ \\\\frac{\\\\pi D^2}{4}=\\\\frac{64D^2}{81}\\\\Rightarrow\\\\frac{\\\\pi}{4}=\\\\frac{64}{81}\\\\Rightarrow\\\\pi=\\\\frac{256}{81} \\$end:math:display$
\$begin:math:display$ \\\\frac{256}{81}=3.1604938271604937\\\\ldots \\$end:math:display$
Archimedes Bounds (Inequality Form)
\$begin:math:display$ 3+\\\\frac{10}{71}<\\\\pi<3+\\\\frac{1}{7} \\$end:math:display$
\$begin:math:display$ 3+\\\\frac{10}{71}=\\\\frac{223}{71}=3.140845070422535\\\\ldots \\$end:math:display$
\$begin:math:display$ 3+\\\\frac{1}{7}=\\\\frac{22}{7}=3.142857142857143\\\\ldots \\$end:math:display$
Continued Fractions and Zu Chongzhi Convergent
\$begin:math:display$ \\\\pi=[3;7,15,1,292,\\\\dots] =3+\\\\cfrac{1}{7+\\\\cfrac{1}{15+\\\\cfrac{1}{1+\\\\cfrac{1}{292+\\\\cdots}}}} \\$end:math:display$
\$begin:math:display$ [3;7]=\\\\frac{22}{7},\\\\quad [3;7,15]=\\\\frac{333}{106},\\\\quad [3;7,15,1]=\\\\frac{355}{113} \\$end:math:display$
\$begin:math:display$ \\\\frac{355}{113}=3.1415929203539825\\\\ldots \\$end:math:display$
Leibniz via Power Series and Integration
\$begin:math:display$ \\\\frac{1}{1+x^2}=\\\\sum_{n=0}^{\\\\infty}(-1)^n x^{2n}\\\\ (|x|<1) \\$end:math:display$
\$begin:math:display$ \\\\int_0^1\\\\frac{1}{1+x^2}\\\\,dx =\\\\int_0^1\\\\sum_{n=0}^{\\\\infty}(-1)^n x^{2n}\\\\,dx =\\\\sum_{n=0}^{\\\\infty}\\\\frac{(-1)^n}{2n+1} \\$end:math:display$
\$begin:math:display$ \\\\frac{\\\\pi}{4}=\\\\sum_{n=0}^{\\\\infty}\\\\frac{(-1)^n}{2n+1} \\\\Rightarrow \\\\pi=4\\\\sum_{n=0}^{\\\\infty}\\\\frac{(-1)^n}{2n+1} \\$end:math:display$
Gaussian Integral in \$begin:math:text$\\\\mathbb{R}^2\\$end:math:text$
\$begin:math:display$ I=\\\\int_{-\\\\infty}^{\\\\infty}e^{-x^2}\\\\,dx \\$end:math:display$
\$begin:math:display$ I^2= \\\\left(\\\\int_{-\\\\infty}^{\\\\infty}e^{-x^2}\\\\,dx\\\\right) \\\\left(\\\\int_{-\\\\infty}^{\\\\infty}e^{-y^2}\\\\,dy\\\\right) = \\\\int_{\\\\mathbb{R}^2}e^{-(x^2+y^2)}\\\\,dx\\\\,dy \\$end:math:display$
\$begin:math:display$ x=r\\\\cos\\\\theta,\\\\ y=r\\\\sin\\\\theta,\\\\ dx\\\\,dy=r\\\\,dr\\\\,d\\\\theta \\$end:math:display$
\$begin:math:display$ I^2=\\\\int_{0}^{2\\\\pi}\\\\int_{0}^{\\\\infty}e^{-r^2}r\\\\,dr\\\\,d\\\\theta \\$end:math:display$
\$begin:math:display$ u=r^2,\\\\ du=2r\\\\,dr\\\\Rightarrow \\\\int_0^{\\\\infty}e^{-r^2}r\\\\,dr=\\\\frac12\\\\int_0^{\\\\infty}e^{-u}\\\\,du=\\\\frac12 \\$end:math:display$
\$begin:math:display$ I^2=\\\\int_0^{2\\\\pi}\\\\frac12\\\\,d\\\\theta=\\\\pi \\\\Rightarrow I=\\\\sqrt{\\\\pi} \\$end:math:display$
Euler Identity from Series
\$begin:math:display$ e^{i\\\\theta}=\\\\sum_{n=0}^{\\\\infty}\\\\frac{(i\\\\theta)^n}{n!} = \\\\left(\\\\sum_{n=0}^{\\\\infty}(-1)^n\\\\frac{\\\\theta^{2n}}{(2n)!}\\\\right) + i\\\\left(\\\\sum_{n=0}^{\\\\infty}(-1)^n\\\\frac{\\\\theta^{2n+1}}{(2n+1)!}\\\\right) = \\\\cos\\\\theta+i\\\\sin\\\\theta \\$end:math:display$
\$begin:math:display$ e^{i\\\\pi}=\\\\cos\\\\pi+i\\\\sin\\\\pi=-1 \\\\Rightarrow e^{i\\\\pi}+1=0 \\$end:math:display$
Zeta Value
\$begin:math:display$ \\\\zeta(s)=\\\\sum_{n=1}^{\\\\infty}\\\\frac{1}{n^s},\\\\quad \\\\zeta(2)=\\\\sum_{n=1}^{\\\\infty}\\\\frac{1}{n^2}=\\\\frac{\\\\pi^2}{6} \\$end:math:display$
\$begin:math:display$ \\\\pi=\\\\sqrt{6\\\\sum_{n=1}^{\\\\infty}\\\\frac{1}{n^2}} \\$end:math:display$
Reference Constant
\$begin:math:display$ \\\\pi=3.14159265358979323846264338327950288419716939937510\\\\ldots \\$end:math:display$
\$begin:math:text$\\\\LaTeX\\$end:math:text$ rendering uses MathJax v3 within the iframe scope.
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